12016 10 (a) A potential divider circuit is set up as shown in Fig. 10.1. 1.10 kΩ 12 V 0.80 kΩ Fig. 10.1 Calculate the potential difference across the 0.80 kΩ resistor. Potential difference =                     V [3] 12016 THIS IS THE END OF THE QUESTION PAPER (b) (i) In the space below, draw a circuit diagram to show how a light dependent resistor, LDR, can be used in a potential divider circuit to automatically switch on a light bulb when it gets dark. [2] (ii) Explain briefly how this circuit allows the light bulb to be turned on automatically. [2] 12016 BLANK PAGE DO NOT WRITE ON THIS PAGE 12016 BLANK PAGE DO NOT WRITE ON THIS PAGE Permission to reproduce all copyright material has been applied for. In some cases, efforts to contact copyright holders may have been unsuccessful and CCEA will be happy to rectify any omissions of acknowledgement in future if notified. For Examiner’s use only Question Number Marks 1 2 3 4 5 6 7 8 9 10 Total Marks Examiner Number 243453 DO NOT WRITE ON THIS PAGE 11378 DATA AND FORMULAE SHEET for use from 2017 onwards Physics [SPH11/SPH21] ADVANCED SUBSIDIARY General Certifi cate of Education Assessment Units AS 1 and AS 2 11378 11378 2 Data and Formulae Sheet for AS 1 and AS 2 Values of constants speed of light in a vacuum c = 3.00 × 108 m s–1 elementary charge e = 1.60 × 10–19 C the Planck constant h = 6.63 × 10–34 J s mass of electron me = 9.11 × 10–31 kg mass of proton mp = 1.67 × 10–27 kg acceleration of free fall on the Earth’s surface g = 9.81 m s–2 electron volt 1 eV = 1.60 × 10–19 J the Hubble constant H0 ≈ 2.4 × 10–18 s–1 Useful formulae The following equations may be useful in answering some of the questions in the examination: Mechanics conservation of energy 1 2 mv 2 – 1 2 mu 2 = Fs for a constant force Waves two-source interference λ = ay d diffraction grating d sinθ = nλ 11378 11378 3 Light lens equation 1 u 1 v 1 f + = Electricity terminal potential difference V = E – Ir (e.m.f., E; Internal Resistance, r) potential divider Vout = R1Vin R1 + R2 Particles and photons Einstein’s equation 1 2 mv max 2 = hf – hf0 de Broglie equation λ = h p Astronomy red shift z = Δλ λ recession speed z = v c Hubble’s law v = H0 d 11378 11378 4