🇬🇧 Limited Time — UK Only·🎓 Free Learning for 1 Month·🤖 Free AI Training Included·📚 4,000+ Lessons · 35,000+ Quizzes·🏆 GCSE Mocks · Olympiad Papers·⚡ Selected Students Only · Limited Places·🎁 Free Value Worth £2,000·🇬🇧 Limited Time — UK Only·🎓 Free Learning for 1 Month·🤖 Free AI Training Included·📚 4,000+ Lessons · 35,000+ Quizzes·🏆 GCSE Mocks · Olympiad Papers·⚡ Selected Students Only · Limited Places·🎁 Free Value Worth £2,000·🇬🇧 Limited Time — UK Only·🎓 Free Learning for 1 Month·🤖 Free AI Training Included·📚 4,000+ Lessons · 35,000+ Quizzes·🏆 GCSE Mocks · Olympiad Papers·⚡ Selected Students Only · Limited Places·🎁 Free Value Worth £2,000·
Back to questions directory
A-Level ChemistryYear 2023Q7

16   7 This question is about carbonyl compounds. (a) Ethanal, CH3CHO, and ethanoic acid, CH3COOH, are both soluble in water but ethanoic acid has a much higher boiling temperature than ethanal. Explain these physical properties of ethanal and ethanoic acid in terms of intermolecular forces. Include a labelled diagram to show why ethanal is soluble in water. (4) .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... Turn over 17   (b) Propanal reacts with hydrogen cyanide in the presence of potassium cyanide to form 2‑hydroxybutanenitrile. C2H5 C H OH CN (i) Draw the mechanism for this reaction. Include curly arrows and any relevant lone pairs and dipoles. (4) (ii) Explain whether or not the 2‑hydroxybutanenitrile formed will be a racemic mixture. (3) .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... 18   (c) Carbonyl compounds can be identified by reacting them with 2,4‑dinitrophenylhydrazine (2,4‑DNPH) to form a solid derivative. These derivatives have characteristic melting temperatures. (i) Identify the steps required to prepare a sample of a pure, dry derivative of a carbonyl compound X. (3) Carbonyl compound X Precipitate in reaction mixture Dry solid derivative Impure solid derivative Purified solid derivative 2,4‑DNPH Step 1 Step 2 Step 3 Step 1 .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... Step 2 .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... Step 3 .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... Turn over 19   (ii) The melting temperature ranges of the derivatives of some carbonyl compounds that could be X are shown in the table. Carbonyl compound Melting temperature range of derivative / °C ethanal 165 – 168 propanal 154 – 156 propanone 127 – 129 cyclohexanone 158 – 160 The melting temperature of the derivative of carbonyl compound X is 156–158 °C and X has an absorption at 1717 cm–1 in its infrared spectrum. Deduce the identity of X. Justify your answer. (2) .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................... (iii) These carbonyl compounds may also be identified using modern methods such as proton NMR spectroscopy. The structure of the pentan‑3‑one derivative formed with 2,4‑DNPH is shown. O2N N CH2 CH3 H H H H N C CH2 CH3 NO2 Label the different proton environments that would give rise to the peaks in the low resolution proton NMR spectrum. (2) (Total for Question 7 = 18 marks)

Paper Source:EDACH339ch0-02-que-20230620.pdf

Get full Socratic AI guidance on this question — free in the Applaa desktop app

Appy Buddy guides you step-by-step toward the answer without giving it away. Type your attempt and get instant, mark-scheme-aware clues that teach you to think like an examiner.

Download Applaa Free →
Applaa Desktop App

Join Applaa Community

Create your own games, learn AI concepts, program interactive apps, and share with a kid-safe community approved by parents. Free forever on Windows and Mac.

Download Free

Available for Windows and macOS · COPPA Compliant

Exam Specification Info

This question is part of the UK A-Level Chemistry syllabus. In the actual exam, structured questions typically require linking specific keywords to gain full marks. Applaa helps you drill these topics.

Syllabus levelAdvanced Level (A-Level)
SubjectChemistry
Official MarksVariable (2–6 marks)